memmove - copy bytes in memory with overlapping areas
#include <string.h> void *memmove(void *s1, const void *s2, size_t n);
The memmove() function copies n bytes from the object pointed to by s2 into the object pointed to by s1. Copying takes place as if the n bytes from the object pointed to by s2 are first copied into a temporary array of n bytes that does not overlap the objects pointed to by s1 and s2, and then the n bytes from the temporary array are copied into the object pointed to by s1.
The memmove() function returns s1; no return value is reserved to indicate an error.
No errors are defined.
None.
None.
<string.h>.
Derived from the ANSI C standard.